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shay68596
18.09.2019 •
Mathematics
Acompany has a budget of $280,000 for computing equipment. tablets cost $500 each, laptops cost $2000 each, and servers cost $5000 each. the company needs 5 times as many tablets as laptops, and two times as many laptops as servers. set this problem up as a system of three linear equations, and use trial and error to determine the approximate number of each type of machine should be purchased.
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Ответ:
The number of tablets 200
the number of laptops 40
and, the number of servers 20
Step-by-step explanation:
Let the number of tablets be 'x'
the number of laptops be 'y'
and, the number of servers be 'z'
According to the given question
Total budget = $280,000
Tablets cost = $500 each
laptops cost = $2000 each
servers cost = $5000 each
Thus,
500x + 2000y + 5000z = 280,000 ..............(1)
also,
x = 5y ................(2)
and,
y = 2z
or
z =
............(3)
substituting y from 2 and 3 in equation 1, we get
(500 × 5y) + (2000 × y) + (5000 ×
) = 280,000
or
2500y + 2000y + 2500y = 280,000
or
7000y = 280,000
or
y = 40
substituting y in equation 2, we get
x = 5 × 40 = 200
substituting y in equation 3 we get
z =![\frac{\textup{40}}{\textup{2}}](/tpl/images/0238/5244/6f1c9.png)
or
z = 20
hence,
the number of tablets 200
the number of laptops 40
and, the number of servers 20
Ответ: