Acompany has three different sites: site 1, site 2 and site 3. at site 1 70% of the employees are bu alum, at site 2 20% of the employees are bu alum, at site 3 10% are bu alum. there are an equal number of employees at each of the three sites. if an employee is randomly selected for employee of the month what is the probability that they are a bu alum

site 1: 70% = .7

site 2: 20% = .2

site 3: 10% = .1

(.7 + .2 + .1)/3  = 1/3

1 out of 3 (1/3)

This is the concept of geometry, we are required to calculate for the length of the sides of the rhombus; we know that a rhombus is a compressed square, this implies that all the sides are equal;
If one of the angles is 110° the other angle will be:
180-110=70°
thus using the cosine rule we can find the side lengths as follows;
c^2=a^2+b^2-2ac Cos C
thus
let side a=b=x in
shorter diagonal=c=4 in
C=70°
substituting this into the formula we get:
4^2=x^2+x^2-2*x*x Cos 70
4^2=2x^2-2x^2(0.3420)
16=2x^2-2x^2(0.3420)
dividing through by 2 we get;
8=x^2-0.3420x^2
8=0.6580x^2
x^2=12.15843
getting the square root of both sides get:
x=sqrt(12.15843
x=3.4869) 
x=3.5 (1 d.p)
the length of the sides is 3.5