Acube made of silver has a density of 10,490 kg/m^3 if one of the sides were doubled without changing the mass of silver how would the density of the cube be changed?

Density will be half of the original density and is equal to 5245 kg/m³

Step-by-step explanation:

Given:

Density of the cube is,

Let the side of the cube be m.

Volume of the cube,

If one side of the cube is doubled, the resulting figure is a cuboid with dimensions

So, new volume is,

Density is given as,

If mass is constant, then density is inversely proportional to its volume.

Therefore,

So, the density of a constant mass is exactly half the original density when one of its sides is doubled.

Step-by-step explanation:

hello :

i (f-g)(3)+(f+g)(0)=f(3)-g(3) +f(0) +g(0)

f(3)=4 and g(3)=0  and f(0)=-2  and g(o)=2

(f-g)(3)+(f+g)(0)=f(3)-g(3) +f(0) +g(0)=4+0-2+2 =4