Add (4x^2-xy-y^2) and (x^2+5xy+8y^2) simplify your

To find a, b, and c, rewrite in the standard form ax2+bx+c=0ax2+bx+c=0.

a=1, b=3, c=0

4x^2-4xy-3\frac{y^2}{2}x^2-5xy-3y^2 is 2

−3x^2 y^2 +8x^2 −18xy−6y^2

Step-by-step explanation:

We're not supposed to help with tests.  The police will be here shortly.

Corresponding parts of congruent triangles are congruent.  We assume the vertex letters correspond and we just write all the corresponding parts.

ΔABC ≅ ΔPQR

so ∠A ≅ ∠P  and  ∠B ≅ ∠Q  and  ∠ C≅ ∠R

and AB ≅ PQ and AC ≅ PR and BC ≅ QR

Now we go through the choices:

B, D