Additive inverse of −9x+3

(3x−4) −(x−5)

Step-by-step explanation:

the lengths of the bases of the trapezoids are
trapezoid A
b=19cm, and B=35cm, b the short base and B the long base

trapezoid B
b=19cm, and B=35cm, b the short base and B the long base

the height is h=15cm

the surface of A is A= hx(b+B) /2

so the surface is A= 15(19+35)/2=405cm²
we know that suface A =surfaceB, so Surface B= 405cm²

finally the total surface painted is 2 x 405cm²= 810cm²

the perimeter of the trapezoid A is PA=17+19+35+17=88cm
the perimeter of the trapezoid B is PB=17+19+35+17=88cm

 one piece of sandpaper will not be enough to sand the edges of one trapezoid