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graymonky12
20.10.2019 •
Mathematics
Afair die will be rolled 11 times. what is the probability that an odd number is rolled exactly 7 times?
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Ответ:
0.161
Step-by-step explanation:
Given:
Number of trials,![n=11](/tpl/images/0336/3586/bce91.png)
Consider the event of rolling odd number as success. There are 3 odd and 3 even numbers in a fair die.
So, probability of success,![p=0.5](/tpl/images/0336/3586/2bd76.png)
Probability of failure,![q=1-p=1-0.5=0.5](/tpl/images/0336/3586/0668c.png)
Number of successes,
From Bernoulli's Theorem, the probability of
successes in
trials is given as,
Here,![x=7,n=11,p=0.5,q=0.5](/tpl/images/0336/3586/81df8.png)
So,![P(X=7)=_{7}^{11}\textrm{C}(0.5)^{7}q^{11-7}\\ P(X=7)=0.161](/tpl/images/0336/3586/36232.png)
Therefore, the probability of getting an odd number exactly 7 times is 0.161.
Ответ:
Marisa’s monthly mortgage payment is $1036
Step-by-step explanation:
The cost of the house is $250,000.
The down payment made is $55,000. The balance to be paid would be
250,000 - 55,000 = $195000
We would apply the periodic interest rate formula which is expressed as
P = a/[{(1+r)^n]-1}/{r(1+r)^n}]
Where
P represents the monthly payments.
a represents the amount of the loan
r represents the annual rate.
n represents number of monthly payments. Therefore
a = $195000
r = 0.049/12 = 0.00408
n = 12 × 30 = 360
Therefore,
P = 195000/[{(1+0.00408)^360]-1}/{0.00408(1+0.00408)^360}]
195000/[{(1.00408)^360]-1}/{0.00408(1.00408)^360}]
P = 195000/{4.33 -1}/[0.00408(4.33)]
P = 195000/(3.33/0.0177)
P = 195000/188.14
P = $1036