alisonlebron15
05.10.2019 •
Mathematics
Afair die with sides numbered 1, 2, 3, 4, 5, and 6 is to be rolled until a number greater than 4 first appears. what is the probability that a number greater than 4 will first appear on the third or fourth roll
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Ответ:
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3
So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3
Ответ:
I am almost positive it is 0.23
Step-by-step explanation: