Thelazysandwich

21.10.2019 • 

Mathematics

Afootball is kicked into the air from an initial height of 4 feet. the height, in feet, of the football above the ground is given by s(t)=-16t^2+50t+4, where t is time, in sevonds, and t > \= 0. at what time will the football be 25 feet above the ground?

a. 3.625 seconds
b. 3.20 seconds
c. 5 seconds or 3.625 seconds
d. 5 seconds or 2.625 seconds

Ответ:

michael3592

07.01.2022

Mathematics

---

S ( t ) = - 16 t² + 50 t + 4
25 = - 16 t² + 50 t + 4
16 t² - 50 t + 21 = 0

t 1 = 2.625 s
t 2 = .5 s
D ) .5 seconds or 2.625 seconds

---

0,0(0 оценок)

Ответ:

karyvillanuevap5w9ym

07.01.2022

Mathematics

---

25 = -16t^2 + 50t + 4
16t^2 - 50t + 21 = 0
16t^2 - 8t - 42t + 21 = 0
8t(2t - 1) - 21(2t - 1) = 0
(8t - 21)(2t - 1) = 0
8t - 21 = 0 or 2t - 1 = 0
t = 21/8 or t = 1/2
t = 2.625 or t = 0.5

---

0,0(0 оценок)

Ответ:

poppy1173

26.04.2021

Mathematics

---

Neither the answer would be I, because you distribute the negative to the (2x-8) making it (-2x+8) then you just combine like terms

---

0,0(0 оценок)