Aline with a slope of 2/5 passed through the point (-2,3). write the equations of the line in point-slope form and graph the line

y - 3 = (2/5)(x + 2)

Step-by-step explanation:

Start with the general point-slope form of the equation of a straight line:

y - k = m(x - h).  Now substitute -2 for h and 3 for k, and also 2/5 for m:

y - 3 = (2/5)(x + 2)

Step-by-step explanation:

Given  the inequality function 12x+7< -11 and 5x-8>40, we are to solve for the value of x. To solve for x, the following steps must be followed.

For the inequality 12x+7< -11

Step 1: Subtract 7 from both sides of the inequality

12x+7-7< -11-7

12x < -18

Step 2: Divide both sides of the inequality by 12

12x/12 < -18/12

x < -3/2 1

For the inequality 5x-8> 40;

Step 1: Add 8 to both sides of the inequality

5x-8+8 > 40+8

5x > 48

Step 2: Divide both sides of the inequality by 5

5x/5 > 48/5

x>48/5 2

Combining equation 1 and 2, we will have;

x < -3/2 and x>48/5

If x>48/5 then 48/5<x

Combining 48/5<x with x < -3/2  will give  48/5<x<-3/2