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16.09.2019 •
Mathematics
Amaintenance man has 12 keys on his key ring. if he tries the keys at random on a storage room door, discarding those that do not work, what is the probability that he will get the door open on his 4th try?
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Ответ:
P(Failure on second try) = 10/11
P(Failure on third try)= 9/10
P(success on fourth try) = 1/9
P(success exactly on fourth try) = 11/12*10/11*9/10*1/9 = 1/12
Ответ:
[(sinФ+ cosФ)/sinФ] / [sinФ + cosФ] = [sinФ + cosФ] / [(cosФ + sinФ) sinФ] =
= 1 /sinФ = cscФ