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brian2913
29.06.2019 •
Mathematics
Amap has a scale of 1cm : 21 km two cities are 3.1 cm apart on the map to the nearest kilometer what is the actual distance corresponding to the map distance
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Ответ:
21km*3.1cm=65.1km. Hope it helps
Step-by-step explanation:
Ответ:
A. X < 3.
Step-by-step explanation:
We have the equation,![3 + \frac{x-2}{x-3} \leq 4](/tpl/images/0156/2606/f3e59.png)
Adding -4 on both sides, we get,
i.e.![\frac{x-2-x+3}{x-3} \leq 0](/tpl/images/0156/2606/e0d3c.png)
i.e.![\frac{1}{x-3} \leq 0](/tpl/images/0156/2606/22e07.png)
So, we have the inequality
.
Its critical points are given by x-3 = 0 which implies x = 3.
Now, we will find the region among the two
and
that satisfies the inequality ![\frac{x-2}{x-3} -1 \leq 0](/tpl/images/0156/2606/e9959.png)
Substitute x = 2 in the above inequality, we get -1 < 0, which is true. Again, substitute x=4 gives 1 < 0, which is false.
As x=4 lie in the region
, it cannot be the solution of the given inequality.
So, the solution of the given inequality is the region
.i.e. x < 3.
Hence. option A is correct.