Amovie theater has 2 ticket prices $9.00 for adults and $6.00 for children. if the box office took in $1614 from the sale of 220 tickets, how many of each kind were sold?

Number of adult tickets sold is 98 and number of children tickets sold is 122.

Solution:

Let the number of adult tickets sold be y and the number of children tickets sold be (220-y).

It is given that price of each adult ticket is $9.00

Therefore the price of ‘y’ adult ticket will be $9.00 (y)

Also it is given that the price of each children ticket is $6.00

Therefore the price of (220-y) children ticket will be $6.00 (220-y)

In the question it is given that the box office collected $ 1614. Thus to find the kind of each tickets sold we use the given equation,

9.00y + 6.00(220-y) = 1614

9.00y + (6.00)(220) - 6.00y = 1614

9.00 y + 1320 -  6.00 y = 1614

3y = 1614 - 1320  

3y = 234

y = 98

Therefore kind of adult tickets sold = 98 and kind of children tickets sold = (220 - 98) = 122 tickets

y = -4/5x + 2

Step-by-step explanation:

y = -4/5x + b

(-2) = -4/5(5) + b

-2 = -4 + b

2 = b