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haydencheramie
11.01.2020 •
Mathematics
Amuseum requires a minimum number of chaperones proportional to the number of students on a field trip. the museum requires a minimum of 3 chaperones for a field trip with 24 students. which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? choose 2 answers:
a. students: 72
minimum of chaperones: 9
b. students: 16
minimum of chaperones: 2
c. students: 60
minimum of chaperones: 6
d. students: 45
minimum of chaperones: 5
e. students: 40
minimum of chaperones: 8
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Ответ:
The combination of values for the students and at least no of chaperones the museum needed is option A and option B.
Given that
There is a minimum no of chaperones required i.e. 3.
And, there are 24 students.
So, if we divided the 24 by 3 so we can get the 8 students for one chaperone.
Now as per the given options:
A.
= 8 students per chaperone.
B.
= 8 students per chaperone.
C.
= 10 students per chaperone.
D.
= 9 students per chaperone.
E.
= 5 students per chaperone.
Therefore we can conclude that the combination of values for the students and at least no of chaperones the museum needed is option A and option B.
Learn more about the proportions here: link
Ответ:
24 students divided by 3 chaperones equals 1 chaperone for every 8 students.
A. 72 / 9 = 8 students per chaperone. This is correct.
B. 16 / 2 = 8 students per chaperone. This is correct.
C. 60 / 6 = 10 students per chaperone. This is not correct.
D. 45 / 5 = 9 students per chaperone. This is not correct.
E. 40 / 8 = 5 students per chaperone. This is not correct.
The 2 correct answers are A and B.
Ответ: