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karlyisaunicorn
19.12.2020 •
Mathematics
An a my baker is making a cake for a Terran visitor. The cake is removed from the over at 357 and cools to 130 after 25 min in a room at 72. How long will it take for the cake to cook off to 90?
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Ответ:
It will take 43.37 mins for the cake to cook off to 90
Step-by-step explanation:
From Newton's law of cooling
Where
and
= constant
From the question,
∴![T_{(t)} = 72 + 285e^{kt}](/tpl/images/1002/8431/41cbd.png)
From the question, the cake cools to 130 after 25 min. Then, we can write that
∴![130 = 72 + 285e^{25k}](/tpl/images/1002/8431/d56a9.png)
Then,
Take the natural log (ln) of both sides
∴![k =\frac{-1.5920}{25}](/tpl/images/1002/8431/fa8a8.png)
Now, to determine how long it take for the cake to cook off to 90
That is,
Take the natural log (ln) of both sides
∴![t = \frac{-2.7621}{-0.06368}](/tpl/images/1002/8431/67a0c.png)
Hence, it will take 43.37 mins for the cake to cook off to 90.
Ответ:
They started working at 11:40.
Step-by-step explanation:
12:30-50
=11:40