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aorilneedshelp6636
21.11.2019 •
Mathematics
An air traffic controller is tracking two planes. to start, plane a is at an altitude of 5000 feet and plane b is at an altitude of 4467 feet. plane a is gaining altitude at 40.5 feet per second and plane b is gaining altitude at 50.75 feet per second. how many seconds will pass before the planes are at the same altitude? what will their altitude be when they're at the same altitude?
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Ответ:
Step-by-step explanation:
52 seconds
7106 feets
Step-by-step explanation:
plane A is at an altitude of 5000 feet.
Plane A is gaining altitude at 40.5 feet per second.
Let t = the time that plane A travels before it attains same altitude with plane B.
Distance = speed × time
Distance travelled in t seconds will be
40.5 × t = 40.5t
Total distance travelled by plane A will be
5000 + 40.5t
plane B is at an altitude of 4467 feet.
Plane A is gaining altitude at 50.75 feet per second.
Let t = the time that plane B travels before it attains same altitude with plane A.
Distance = speed × time
Distance travelled in t seconds will be
50.75 × t = 50.75t
Total distance travelled by plane A will be
4467 + 50.75t
For both planes to be at the same altitude, their total distance must be equal. Therefore,
5000 + 40.5t = 4467 + 50.75t
5000-4467 = 50.75t- 40.5t
533 = 10.25t
t = 533/10.25 = 52 seconds
It will take 52 seconds for both planes to be at the same altitude.
Altitude of plane A will be
5000 + 40.5 × 52 = 7106 feets
Altitude of plane both planes will be
7106 feets
Ответ:
0.11
Step-by-step explanation:
7.26 / 66 = 0.11
hope this helps <3