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hannahmayline
04.12.2020 •
Mathematics
An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the heading to 310. Determine how far the plane is from the airport at 1:00 a.M.
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Ответ:
2330.51 miles
Step-by-step explanation:
Given that the speed of the airplane = 610 mph.
The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.
So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.
As, distance = time x speed, so
The distance covered at 270 degrees,
miles.
The distance covered at 310 degrees,
miles.
Total distance covered, d, is the magnitude of the sum of vectors
and
as shown in the figure.
The angle between the vectors
and
,
degree.
Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},
Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.
Ответ:
60 dogs are male and over 3 years out of total 150 male dogs.
Step-by-step explanation:
Total no. of dogs are 500
Males are 500 x 0.3 = 150
Over 3 years are 150 x 2/5 = 60