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aaronolivera200161
25.02.2020 •
Mathematics
An archer hits a bull’s-eye with a probability of 0.09, and the results of different attempts can be taken to be independent of each other. If the archer shoots nine arrows, what is the variance of the number of bull's-eyes scored?
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Ответ:
Variance = 0.858
Step-by-step explanation: The variance formulae for a probability distribution is given below as
Variance = √npq
Where n = number of times experiment was performed = 9
p = probability of success = 0.09
q = probability of failure = 1 - p = 1 - 0.09 =0.91
Variance = √9×0.09×0.91
Variance = √0.7371
Variance = 0.858
Ответ: