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astultz309459
14.07.2019 •
Mathematics
An architect created a scale model of purdue university's new construction area.
the scale model is 2 in to every 25 feet. purdue's bell tower is 160 feet tall. how
tall is the scale model of this bell tower?
a) 3.2 in
b) 6.4 in
c) 12.8 in
d) 25.6 in
Solved
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Ответ:
C) 12.8 in
Step-by-step explanation:In this question, it is asking you to find how tall the scale model of the Bell Tower is (specifically in inches).
To solve this problem, we would get some information from the question that will help us get to the answer.
Important information:
Scale model is 2 inches to every 25 feetBell Tower is 160 feet tallWith the information that we got above, we can solve the question.
What we do first is divide 160 by 25 in order to see how many feet the scale model is.
You should get 6.4 when you divide. This means that the height of the scale model is 6.4 feet.
But, we are not done yet. We need to find how high the scale model is in inches.
We would just multiply 6.4 by 2 in order to get the height in inches.
You should get 12.8 as your answer.
This means that the height of the scale model is 12.8 inches, meaning that the correct answer choice is c) 12.8 in
I hope this helps you out.Good luck on your academics.Have a fantastic day!Ответ:
a. You cannot conclude that the true mean of the inside diameter is different from 1.5 inches.
b. p-value: 0.992
Step-by-step explanation:
Hello!
To test the hypothesis that "The true mean of inside diameter is different from 1.5 inches."
Let's define the study variable:
X: "inside diameter of a bearing"
X~N(μ;
)
With known standart derivation σ= 1 inch
Sample taken:
n= 25 bearings
X(bar)= 1.4975 inches
>Statistical hyphotesis for this problem
H₀: μ = 1.5
H₁: μ ≠ 1.5
>Level of significance
α: 0,01
>Since the variable has a normal distribution and the population standard desviation is known the mos accurate statistical to use is:
>The critical region for this test is two-tailed, that means you'll have two critical values.
This means, you'll reject the null hyphotesis if your
is ≤ -2,58 or if it is ≥ 2,58
Now calculate the
value by replacing the formula:
Since the calculated Z value is between the non rejection area, the test is not statistically significant. In other words, you cannot conclude that the true mean of the inside diameter is diferent from 1.5 inches.
b. To calculate the p-value, you have to look for the probability of the calculated Z-value
P(Z≤-0.0125) ≅ 0,496
The p-value above is one tailed, to have the p-value for this thest you need to simply multiply it by 2, so the p-value for the test is 0.992 (aprox)