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mattwe4567893987654
29.01.2020 •
Mathematics
An arrow is shot vertically upward at a rate of 220ft/s. use the projectile formula h=? 16t2+v0t to determine at what time(s), in seconds, the arrow is at a height of 400ft. round your answer(s) to the nearest tenth of a second.
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Ответ:
t1 = 2.2 s
t2 = 11.5 s
Step-by-step explanation:
The general quadratic formula for these cases is
h(t) = h0 + v*t + 0.5*a*t^2
Where
a = the acceleration of the body. In this case, since the arrow is going upwards, we take the acceleration of the gravity.
a = -32.2 feet/s^2 = -9.8 m/s^2
v = the velocity
v = 220 ft/s
h0 = the initial distance. We assume it launched from ground
h0 = 0
h(t) = - 16.1*t^2 + 220*t
See, attached picture
When the height h = 400 ft
- 16.1*t^2 + 220*t = 400
t1 = 2.159 s ≈ 2.2 s
t2 = 11.505 s ≈ 11.5 s
Ответ:
x²+2x=17
Group terms that contain the same variable
(x²+2x)=17
Complete the square. Remember to balance the equation
(x²+2x+1)=17+1
Rewrite as perfect squares
(x+1)²=18
x+1=(+/-)√18
x=(+/-)√18-1
x1=√18-1> 3.24
x2=-√18-1> -5.24
the answer is
the option
4.) 3.24, –5.24