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Garrell
16.11.2019 •
Mathematics
An automotive part must be machined to close tolerances to be acceptable to customers. production specifications call for a maximum variance in the lengths of the parts of .0004. suppose the sample variance for 30 parts turns out to be s 2 = .0005. use = .05 to test whether the population variance specification is being violated.
state the null and alternative hypotheses.
h0 : σ2
ha : σ2
calculate the value of the test statistic (to 2 decimals).
the p-value is what is your conclusion?
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Ответ:
Since 36.25 is less than 42.56, we do not reject H_o.
Step-by-step explanation:
Given n=30, s^2=0.0005
The test hypothesis is
H_o:σ^2=0.0004
Ha:σ^2 not equal to 0.0004
The test statistic is
χ^2= (n-1)×s^2/σ^2 = (30-1)*0.0005/0.0004=36.25
Given a=0.05, the critical value is χ-square with 0.95, d_f=n-1=29= 42.56 (check χ-square table)
Since 36.25 is less than 42.56, we do not reject H_o.
So we can conclude that the population variance specification is being violated.
Ответ:
Step-by-step explanation:
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