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charae0185
22.03.2020 •
Mathematics
An envelope measures 5 inches by 12 inches. A pencil is placed in the envelope at a diagonal. What is the maximum possible lenght of the pencil?
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Ответ:
the maximum possible length of the pencil is 13 inches
Step-by-step explanation:
Here we have , An envelope measures 5 inches by 12 inches. A pencil is placed in the envelope at a diagonal. We need to find What is the maximum possible length of the pencil . Let's find out:
We know that maximum length which can be fitted in envelope will be the length of diagonal of envelope . So
By Pythagoras theorem
⇒![Diagonal^2 = length^2 +breadth^2](/tpl/images/0558/1532/f9eaf.png)
⇒![Diagonal^2 =5^2 +12^2](/tpl/images/0558/1532/0c51c.png)
⇒![Diagonal^2 =25 +144](/tpl/images/0558/1532/1132a.png)
⇒![Diagonal^2 = 169](/tpl/images/0558/1532/e670a.png)
⇒![\sqrt{Diagonal^2} = \sqrt{169}](/tpl/images/0558/1532/51b01.png)
⇒![Diagonal= 13 inch](/tpl/images/0558/1532/45527.png)
Therefore, the maximum possible length of the pencil is 13 inches .
Ответ:
x = 3y + 51
4x - 2y = - 10...,..2
substituting value of x in equation 2
4(3y+5)-2y=-10
12y+20-2y=-10
10y=-10-20
y=-30/10=-3 is answer
substituting value of y in equation 1
x=3×-3+5=-9+5=-4 is answer