flameftw2005

05.05.2020 • 

Mathematics

An experiment was performed to compare the fracture toughness of high-purity 18 Ni maraging steel with commercial-purity steel of the same type. For m = 34 specimens, the sample average toughness was x = 65.2 for the high-purity steel, whereas for n = 36 specimens of commercial steel y = 59.7. Because the high-purity steel is more expensive, its use for a certain application can be justified only if its fracture toughness exceeds that of commercial-purity steel by more than 5. Suppose that both toughness distributions are normal.

Assuming that Ï1 = 1.2 and Ï2 = 1.1, test the relevant hypotheses using α = 0.001. (Use μ1 â μ2, where μ1 is the average toughness for high-purity steel and μ2 is the average toughness for commercial steel.)

Ответ:

clipsyden

23.10.2020

Mathematics

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10 chairs

Step-by-step explanation:

The circular stage will be treated as a circle.

The 78.5 feet surrounds the circle so this is the circumference.

You need to find the diameter because that is the distance across the circle.

Circumference = π * diameter

Diameter = Circumference / π

= 78.5 / 3.14

= 25 feet

The distance across the circle is 25 ft, the number of chairs that can fit is therefore:

= Distance / Width of chair

= 25 / 2.5

= 10 chairs

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