isabelacarraler
16.04.2020 •
Mathematics
An object attached to a spring undergoes simple harmonic motion modeled by the differential equation m d 2 x d t 2 + k x = 0 where x ( t ) is the displacement of the mass (relative to equilibrium) at time t , m is the mass of the object, and k is the spring constant. A mass of 13 kilograms stretches the spring 0.9 meters. Use this information to find the spring constant. (Use g = 9.8 meters/second2) k = The previous mass is detached from the spring and a mass of 19 kilograms is attached. This mass is displaced 0.1 meters below equilibrium and then launched with an initial velocity of − 2 meters/second. Write the equation of motion in the form x ( t ) = c 1 cos ( ω t ) + c 2 sin ( ω t ) . Do not leave unknown constants in your equation. x ( t ) = Rewrite the equation of motion in the form x ( t ) = A sin ( ω t + ϕ ) . Do not leave unknown constants in your equation. x ( t ) =
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Ответ:
10.3 is already rounded to the nearest tenth.
Step-by-step explanation:
Where the 3 is is the tenths place.