An object is launched from a platform.
its height (in meters), x seconds after the launch, is modeled by
h(x)=-5(x+1)(x-9)
what is the height of the object at the time of launch?
meters
answer as soon as possible !

45 meters

Step-by-step explanation:

If x represents the seconds after the launch, then the time of launch is when x=0 so you just need to solve for h(0)

h(0) = -5(1)(-9)

h(0) = 45

45 m

Step-by-step explanation:

At the time of launch, the time x = 0

Substitute x = 0 into h(x)

h(0) = - 5 (0 + 1)(0 - 9) = - 5(1)(- 9) = - 5 × - 9 = 45

1/4 gallon= 2/3Bin From the problem.So multiply both sides by three to get rid of the 3 in the 2/3 Bin. (3/4=2Bin) Then divide by two to cancel out the 2Bin so there's your answer 3/8Gallons in a Bin. 3/8=Bin I'm essentially dividing 1/4 by 2/3