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kaylaamberd
01.04.2020 •
Mathematics
An oil slick is expanding as a circle. The radius of the circle is currently 2.5 inches and is increasing at a rate of 6.5 inches per hour. Express the area of the circle, A as a function of h, the number of hours elapsed.
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Ответ:
So we can express the radius in terms of the hours elapsed like this:
And the reason of this is because each hour the radius increase 6.5 inches, and if we replace in the formula of area we got:
And this function would represent the area of the circle as function of the hours elapsed,![h\geq 0](/tpl/images/0576/1252/e4bf8.png)
Step-by-step explanation:
For this case we know the radius of a circle given
and we also know the incresing rate for the radius:
And we want to express the are of the circle A as a function of h = the number of hours elapsed.
We know that the area of a circle is given by:
So we can express the radius in terms of the hours elapsed like this:
And the reason of this is because each hour the radius increase 6.5 inches, and if we replace in the formula of area we got:
And this function would represent the area of the circle as function of the hours elapsed,![h\geq 0](/tpl/images/0576/1252/e4bf8.png)
Ответ:
Correct 2/3 < 3/4
Step-by-step explanation:
We will compare the following two fractions:
2/3 and 3/4
First we will find common denominator:
The common denominator for 3 and 4 is 12, then we will multiply
first fraction with 4 and second with 3 and get:
8/12 and 9/12 and we conclude that 9/12 is greater than 8/12
respectively that 3/4 is greater than 2/3
Second we will find common numerator:
The common numerator for 2 and 3 is 6, then we will multiply
first fraction with 3 and second with 2 and get:
6/9 and 6/8 and we conclude that 6/8 is greater than 6/9, the reason is, the greater the fraction, the smaller the denominator
respectively that 3/4 is greater than 2/3
God is with you!!!