Mathematics: An urn contains 6 red balls, 8 green balls, and 10 white balls. If balls are selected one by one (without replacing them after they are selected) what is the probability that at least two balls must be selected in order to get a green ball. g

An urn contains 6 red balls, 8 green balls, and - id681010075621, damilysgonzalez2

Ответ:

barstr9146

14.02.2022

Mathematics

0.43478

Step-by-step explanation:

From the information given:

$The \ required \ probability = P(1st ball = red) \times P(2nd ball = red) + P(1st ball = red) \times P(2nd ball = white) + P(2nd ball = red) \times P(1st ball = white) + P(1st ball = white) \times P(2nd ball = white)$

$= \dfrac{6}{6+8+10}\times \dfrac{5}{5+8+10} + \dfrac{6}{6+8+10} \times \dfrac{10}{5+8+10} + \dfrac{10}{6+8+10} \times \dfrac{6}{5+8+10} \times \dfrac{10}{6+8+10} \times \dfrac{9}{5+8+9}$

$=(\dfrac{6}{24}\times \dfrac{5}{23})+ (\dfrac{6}{24}\times \dfrac{10}{23}) +( \dfrac{10}{24}\times \dfrac{6}{23} ) + (\dfrac{10}{24}\times \dfrac{9}{23})$

= 0.05434782609 + 0.1086956522 + 0.1086956522 + 0.1630434783

= 0.4347826088

≅ 0.43478

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Ответ:

Osmin

06.07.2021

Mathematics

D.) A reflection of the shape across the y-axis and an 180 degree rotation around the origin and A.

Step-by-step explanation:

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An urn contains 6 red balls, 8 green balls, and 10 white balls. If balls are selected one by one (without replacing them after they are selected) what is the probability that at least two balls must be selected in order to get a green ball. g

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