Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an hourly rate of \$28$28dollar sign, 28. The plumber only charges for a whole number of hours. Anand would like to spend no more than \$250$250dollar sign, 250, and he wonders how many hours of work he can afford. Let HHH represent the whole number of hours that the plumber works.

Step-by-step explanation:

 Let H represent the whole number of hours that the plumber works.

given that the fixed cost is $65

and the hourly cost is $28

also given that Anand has a total of $250 with him

the total cost can be expressed in terms of the number of hours H as

250=65+28H

we can now solve for H

250-65=28H

185=28H

divide both sides by 28

H=185/28

H=6.60714285714

"The plumber only charges for a whole number of hours."

So the number of hours Anand can afford is 6hours

  x^3 +8x^2 +11x -20

Step-by-step explanation:

(x+5)  * (x^2+3x-4)

Multiply x * (x^2+3x-4)   = x^3 + 3x^2 -4x

Multiply 5 *  (x^2+3x-4)  =          5x^2+ 15x  -20

Add                                  

                                             x^3 +8x^2 +11x -20