Anationwide study of american homeowners revealed that 65% have one or more lawn mowers. a lawn equipment manufacturer, located in omaha, feels the estimate is too low for households in omaha. find the p-value for a test of the claim that the proportion with lawn mowers in omaha is higher than 65%. among 497 randomly selected homes in omaha, 340 had one or more lawn mowers.

0.9192433

Step-by-step explanation:

Given : A nationwide study of American homeowners revealed that 65% have one or more lawn mowers.

i.e. Population proportion :

A  lawn equipment manufacturer, located in Omaha, feels the estimate is too low for households in Omaha.

Then, his hypothesis will be :-

Since, the alternative hypothesis is left tailed , so the test is a left-tailed test.

Sample size : n= 497

The sample proportion of people ad one or more lawn mowers=

Test statistic for proportion :-

i.e.

Now, by using the standard normal table for z , we have

P-value (left tailed) =

The circle is centered at (5, −7) and has a radius of 7.

Step-by-step explanation:

The standard form of the equation of a circle with center (a,b) and radius r is given as:

The given equation is

We rewrite to look like the stay form:

We now compare the two equations to get:

a=5, b=-7 and r=7.

Therefore the circle is centered at (5,-7) and has a radius of 7