Andrew invested $10,000 in two mutual funds. one of the funds rose 6% in one year, and the other rose 9% in one year. if andrew’s investment rose a total of $684 in one year, how much did he invest in each mutual fund?

Andrew invested $7,200 in the first fund (at 6%) and $2,800 in the second fund (at 9%)

Step-by-step explanation:

Let $x be Andrew's investment in 1st mutual fund. Then $(10,000-x) is Andrew's investment in 2nd mutual fund.

1st fund:

P = x

r = 0.06 (or 6%)

t = 1 year

Interest

2nd fund:

P = 10,000 - x

r = 0.09 (or 9%)

t = 1 year

Interest

If Andrew’s investment rose a total of $684 in one year, then

3/2= 12/x

Step-by-step explanation:

Side length of square = 12 inches.

Now we are given that Michel uses the scale drawing and the scale factor to enlarge a square

Scale Factor = 3 in. : 2 m

Now let the side of enlarged square be x

So, Using scale factor

Thus the side of enlarged square is 8 m

So,  proportion could Michel use to solve the side length, x, of the enlarged square

Hence Option D is correct.

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