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Demondevilg
01.07.2019 •
Mathematics
Andrew is 3 times his son’s age. 10 years ago, he was 5 times his son’s age. what are their present ages? show your work.
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Ответ:
STEP-BY-STEP SOLUTION:
We will be using simultaneous equations to solve this problem.
Let's establish the two equations we will be using to solve the problem.
Let Andrew's current age = a
Let Andrew's son's current age = s
Equation No. 1 -
a = 3s
Equation No. 2 -
a - 10 = 5s
To begin with, we will substitute the value of ( a ) from the first equation into the second equation to solve for ( s ).
Equation No. 2 -
a - 10 = 5s
( 3s ) - 10 = 5s
3s - 5s = 10
- 2s = 10
s = 10 / - 2
s = - 5
Next we will substitute the value of ( s ) from the second equation into the first equation to solve for ( a ).
Equation No. 1 -
a = 3s
a = 3 ( - 5 )
a = - 15
FINAL ANSWER:
Therefore, the present age of Andrew is - 15 and the present age of Andrew's son's is - 5.
It isn't possible for someone to be negative years old, but this is the answer that I ibtained from the equations.
Hope this helps! :)
Have a lovely day! <3
Ответ:
reread the question.. if you do, it has all of the parts you need to answer the question...
Step-by-step explanation: