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josuep425
18.07.2019 •
Mathematics
Andy had a snowball (a perfect sphere) with a radius of 3 \text{ cm}3 cm3, space, c, m. he wanted the snowball to be bigger, so he spent 444 seconds packing more snow onto it. each second he spent packing, the snowball's radius increased by 0.25 \text{ cm}0.25 cm0, point, 25, space, c, m. what is the ratio of the current volume of the snowball to the original volume of the snowball? choose 1
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Ответ:
V1 = (4/3) * (pi) * (r1 ^ 3)
V1 = (4/3) * (3.14) * (3 ^ 3)
V1 = 113.04 cm ^ 3
The current volume is given by:
V2 = (4/3) * (pi) * ((r1 + 0.25 * t) ^ 3)
V2 = (4/3) * (3.14) * ((3 + 0.25 * 4) ^ 3)
V2 = 267.9466667 cm ^ 3
The relation of volumes is:
V2 / V1 = 64/27
The ratio of the current volume of the snowball to the original volume of the snowball is:
V2 / V1 = 64/27
Ответ:
Yes plz
Step-by-step explanation: and press thanks