jennymares
23.08.2019 •
Mathematics
Anew youth sports center is being built in hadleyville. the perimeter of the rectangular playing field is 536 yards. the length of the field is 22 yards less than quadruple the width. what are the dimensions of the playing field?
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Ответ:
W = 58 yards, L = 210 yards
Step-by-step explanation:
P = 2 (L + W)
L = 4w - 22
P = 2 (4W - 22 + W)
536 = 8W - 44 + 2W
536 = 10W - 44
10 W = 536 + 44
10W = 580
W = 58 yards
Since L = 4W - 22
L = 4 (58) - 22
L = 232 - 22
L = 210 yards
Ответ: