Mathematics: Angie is x years old. her sister is 12 years older than her while their mother is twice as old as her sister. betty is 3 years younger than angie while betty s mother is 4 times as old as betty. express angie s mother s age in terms of x. express betty s mother s age in terms of x. if angie s mother is 6 years older than betty s mother, find angie s age

Angie is x years old. her sister is 12 years older

Ответ:

naomirice24

15.01.2022

Mathematics

Step-by-step explanation:

Parking lot:

Angie=x

Sister=x+12

Amom=2•(sister) or 2(x+12)=2x+24

Betty=x-3

Bmom=4•(betty) or 4(x-3)=4x-12

Part A: Amom=2x+24

Part B: Bmom=4x-12

PartC:

x=angie

Amom=Bmom+6

2x+24=4x-12+6

2x+24=4x-6

24-6=4x-2x

18=2x

9=x

Angie is 9 years old.

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Ответ:

roseemariehunter12

10.12.2022

Mathematics

$\dfrac{y+1}{y+2}+\dfrac{y+8}{y+9}=\dfrac{y+2}{y+3}+\dfrac{y+7}{y+8}$

Write all fractions in terms of a common denominator:

$\dfrac{y+1}{y+2}=\dfrac{(y+1)(y+9)(y+3)(y+8)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+8}{y+9}=\dfrac{(y+8)^2(y+2)(y+3)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+2}{y+3}=\dfrac{(y+2)^2(y+9)(y+8)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+7}{y+8}=\dfrac{(y+7)(y+2)(y+9)(y+3)}{(y+2)(y+9)(y+3)(y+8)}$

Then move all fractions to one side and simplify the numerator:

$\dfrac{(y+1)(y+9)(y+3)(y+8)+(y+8)^2(y+2)(y+3)-(y+2)^2(y+9)(y+8)-(y+7)(y+2)(y+9)(y+3)}{(y+2)(y+9)(y+3)(y+8)}=0$

The numerator dictates when the fraction reduces to 0. The denominator can never be 0, so we know that y cannot take any of the values -2, -9, -3, nor -8.

So the equation reduces to

(y+1)(y+9)(y+3)(y+8)+(y+8)^2(y+2)(y+3)-(y+2)^2(y+9)(y+8)-(y+7)(y+2)(y+9)(y+3)=0

Expand the left side; you would end up with

-6(2y+11)=0

2y+11=0

2y=-11

$\implies\boxed{y=-\dfrac{11}2}$

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