Angle and find the reference angle. t=5pi/4

Perimeter of ABCD = 21.58 units

Step-by-step explanation:

Distance formula:-

Le (x₁,y₁) and (x₂,y₂) be the two end points of a line segments.Then length of segment = √[(x₂ - x₁)² + (y₂ - y₁)²]

It is given that,

ABCD is a quadrilateral  A(-3,2) B(4,2) C(3,-3) D(-3,3)

To find the side length of quadrilateral  

A(-3,2) ,  B(4,2),  C(3,-3) and  D(-3,3)

AB =  √[(4 --3)² + (2 - 2)²] =  √[(4 +3)² + 0]  = 7

B(4,2) C(3,-3)

BC = √[(3 - 4)² + (-3 - 2)²]  = √26 = 5.1

CD = √[(-3 - 3)² + (3 - -3)²]  =√72 = 8.48

AD =  √[(-3 - -3)² + (3 - 2)²]  =1

To find perimeter of ABCD

Perimeter = AB + BC + CD + AD = 7 + 5.1 + 8.48 + 1= 21.58