ScardeySpiderAlt
07.04.2020 •
Mathematics
Answer in the 10-1 quiz intro to circles, central angles, arcs, and chord
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Ответ:
The measures of the angles are:
Arc JK is 27 degrees.Arc NJ is 153 degrees.Arc JL is 117 degrees.Angle KNM is 207 degrees.Angle MJL is 297 degrees.Angle JLK is 333 degrees.From the attached image, we have:
The center of the circle is P.The diameters are lines JM and NK.The above highlights mean that:
So, we have:
Substitute 63 for MPL
Subtract 63 from both sides
means that
So, arc JK is 27 degrees
Arc NJ is calculated using:
--- measure of angle in a semicircle
So, we have:
Arc JL is calculated using:
So, we have:
The measure of angle KNM is calculated using:
So, we have:
The measure of angle MJL is calculated using:
So, we have:
Lastly, the measure of angle JLK is calculated using:
So, we have:
Read more about circles, central angles, arcs, and chord at:
link
Ответ:
a. 27
b. 153
c. 117
d. 207
e. 297
f.333
Step-by-step explanation:
In the circle, the center point is P, JM and NK are two diameters of the circle
=> JM intersects NK at point P
=> ∠MPN = ∠JPK
As P is on line segment NK
=> ∠MPN + ∠MPL + ∠LPK = 180°
Given that: ∠MPL = 63°; ∠LPK = 90°
=> ∠MPN + 63° + 90° = 180°
=> ∠MPN = 180° - 90° - 63° = 27°
=> ∠MPN = ∠JPK = 27°
As P is on line segment MK=J
=> ∠MPN + ∠NPJ = 180°
=> 27 + ∠NPJ = 180
=> m∠NPJ = 180 - 27 = 153°
As P is the center point of the circle and J, K, L, M, N are points on the circle, so that we have:
+) m arc JK = m∠JPK = 27°
+) m arc NJ = m∠NPJ = 153°
+) m arc JL = m∠JPL = m∠JPK + m∠KPL = 27 + 90 = 117°
+) m arc KNM = m arc KN + m arc NM = 180° + ∠MPN = 180 + 27 = 207°
+) m arc MJL = 360° - m arc ML = 360° - ∠MPL = 360 - 63 = 297°
+) m arc JLK = 360° - m arc JK = 360 - 27 = 333°
Ответ:
303.14159265
Step-by-step explanation:
3.14+300= 303.14