Answer this question, so i can go to sleep

Perimiter=area around
just add them

triangle=3√147+2√108+2√48+3√75+6√12
we can simplify them
3√147=3(7)√3=21√3
2√108=2(6)√3=12√3
2√48=2(4)√3=8√3
3√75=3(5)√3=15√3
6√12=6(2)√3=12√3

so
21√3+12√3+8√3+15√3+12√3=68√3

then the nex one
the perimiter is 4 times the one side
4 times 1/3√63=(4/3)√63
(4/3)√63=(4/3)(3)√7=4√7

the last one
P=2(L+W)
P=2(2√48+4√75+(1/4)√100)
P=2(2(4)√3+4(5)√3+(1/4)10)
P=2(8√3+20√3+(10/4))
P=2(28√3+5/2)
P=56√3+5

so the perimiters are

68√3≈117.779 for the traingle
4√7≈10.583 for the sqare
56√3+5≈101.995 for the rectangle

so the one with the largets perimter is the triangle

-reflection only

-rotation, then translation

on edgenunity (the test) this is the correct )