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jusicca1109
02.09.2019 •
Mathematics
Anumeha is mowing lawns for a summer job. for every mowing job, she charges an initial fee of \$10$10dollar sign, 10 plus a constant fee for each hour of work. her fee for a 555-hour job, for instance, is \$35$35dollar sign, 35. let f(t)f(t)f, left parenthesis, t, right parenthesis denote anumeha's fee for a single job fff (measured in dollars) as a function of the number of hours ttt it took her to complete it. write the function's formula.
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Ответ:
Since the problem specifically states that the fee of Anumeha is constant for the each hour of work with an initial fee of $10, therefore this means that the function must be linear. The general form of a linear function is in the form of:
y = m x + b
In this case, y = f and x = t, therefore:
f = m t + b
where f is a single job, m is the slope of the linear function, t is number of hours and b is the y intercept
The y intercept (b) is the value of f when t = 0, in this case this is equivalent to the initial fee (before any work is done) therefore:
b = 10
Thus the equation becomes:
f = m t + 10
We are also given that for t = 5, the total fee is $35 so f = 35. Therefore calculating for m:
35 = m (5) + 10
5m = 25
m = 5
Thus,
f = 5 t + 10
Ответ:
39
Step-by-step explanation:
His number is x.
"If you subtract 19 from my number"
x - 19
"and multiply the difference by - 7"
-7(x - 19)
"the result is -140."
-7(x - 19) = -140
Divide both sides by -7.
x - 19 = 20
Add 19 to both sides.
x = 39
The number is 39.