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brose0707
24.06.2021 •
Mathematics
Anyone know how to do this??
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Ответ:
csc²(x)
Step-by-step explanation:
csc(x) = 1/sin(x)
sin²(x) + cos²(x) = 1
=> cos²(x) = 1 - sin²(x)
cos(2x) = cos²(x) - sin²(x) = (1 - sin²(x)) - sin²(x) =
= 1 - 2×sin²(x)
=> 2×sin²(x) = 1 - cos(2x)
sin²(x) = 1/2×(1-cos(2x))
=> 1 - cos(2x) = 2×(1/2×(1-cos(2x)) = 2×sin²(x)
=> 2 / (1-cos(2x)) = 2 / (2×sin²(x)) = 1/sin²(x) =
= 1/sin(x) × 1/sin(x) = csc(x)×csc(x) = csc²(x)
Ответ:
Trong một tam giác vuông, bình phương của cạnh huyền bằng tổng các bình phương của hai cạnh góc vuông.
ΔABC∆ABC vuông tại AA thì ta có:
BC2=AB2+AC2BC2=AB2+AC2
Step-by-step explanation: