Aparachutist's rate during a free fall reaches 45 meters per second. what is this rate in feet per second? at this rate, how many feet will the parachutist fall during 15 seconds of free fall? in your computations, assume that 1 meter is equal to 3.3 feet. do not round your answers.

198 feet1 meter 
X 
1 second3.3 feet 

198 
meters per second 
3.3 

60 meters per secondANSWER 

60 m/sec X 15 sec = 900 feetANSWER 

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A PRESENT FOR YOU 
Ask someone to write a number, say a five-digit number. 
(Can be a 2-digit3-digit4-digitect 
Suppose the number written is 
57836 
Now, without showing the asker, you write a number on 
a sheet of paper and keep it folded. You have to write the 
number by subtracting 2 from the above number and 
adding 2 in front which will be 
257834 
Next, ask the person to write another five-digit number 
below his original number. Suppose he writes 37589. 
So you now have... 
57836 
37589 
Now you write a five-digit number below it in such a 
way that each digit is 9 minus digit above. You now have... 
57836 
37589 
62410 
Ask the person to add one more 5-digit number. If he 
adds 54732, you add below it 45267. Note that you decided 
the number by subtracting each of his digit from 9. 
Thus, you now have 
57836 
37589 
62410 
54732 
45267 
Next, ask him to add all the number and he gets 257834 
Show him the number which you had written as an answer 
to this addition earlier in the folded paper and surprise him.

I can’t really do long division on a phone so, extended techniques are required.

(x^3 - 2x^2 + 6x + 3)/(x-3)

= (x^3 - 3x^2 + (x^2 - 6x + 9)+ 12x - 6)/(x-3)

= (x^2(x-3) + (x-3)^2 + 6(2x - 1))/x-3

= x^2 + x - 3 + 6(2x - 1)/(x-3)

or

= x^2 + x - 3 remainder 12x - 6

or, in the form p(x) = q(x)d(x) + r(x):

(x^3 - 2x^2 + 6x + 3) = (x^2 + x - 3)(x - 3) + (12x - 6)

which implies that the quotient q(x) = (x^2 + x - 3) and remainder r(x) = 12x - 6