winterblanco
23.08.2019 •
Mathematics
Apassword is 4 characters long and must consist of 3 letters and 1 of 10 special characters. if letters can be repeated and the special character is at the end of the password, how many possibilities are there?
a. 175,760
b. 456,976
c. 703,040
d. 1,679,616
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Ответ:
number of letters:26
In each 3 first position ,we can put 26 possibilities
=>26^3
Last position: 10 posibilities
==>26^3*10 =175 760
Answer A
Ответ:
26 letters
3 places
26*26*26
10 characters
26*26*26*10=175760 posibiities
A
Ответ:
use the formula y = a(x-h)^2 + k
the a stretches or flattens the parabola,
The h shifts left to right , and the k shifts up/down
Step-by-step explanation: