Apizza restaurant markets 3 versions of its crazy combo: combo 1 contains
3 cheese pizzas and 1 pepperoni pizza, combo 2 contains 2 cheese pizzas
and 2 pepperoni pizzas, and combo 3 contains 1 cheese pizza and 3
pepperoni pizzas. mr. jenkins orders 5 combo 1s, 2 combo 2s, and 3 combo 3s.

which of the following is a valid conclusion?

a. the probability that mr. jenkins will choose a pepperoni pizza at
random is 11/40.

b. the probability that mr. jenkins will choose a
pepperoni pizza at random is 9/10.

c. the probability that
mr. jenkins will choose a cheese pizza at
random is 9/20.

d. the probability that mr. jenkins will choose a cheese pizza at
random is 11/20.

Step-by-step explanation:

combo 1 : 3 cheese and 1 pepperoni

combo 2: 2 cheese and 2 pepperoni

combo 3: 1 cheese and 3 pepperoni

he chooses :

5 combo 1's : so thats (5 * 3) = 15 cheese, (5 * 1) = 5 pepperoni

2 combo 2's(2*2) = 4 cheese and (2 * 2) = 4 pepperoni

3 combo 3's3(3 * 1) = 3 cheese and (3 * 3) = 9 pepperoni

added = a total of 22 cheese and 18 pepperonithats 40 pizzas

so the probability that he will randomly pick a pepperoni is 18/40 which reduces to 9/20

the probability that he will pick a cheese is 22/40 which reduces to 11/20

so ur answer is D. <===

No

Step-by-step explanation:

2(x+4)+4 distributing the 2 comes out as 2x+8+4 and then simplified comes out to 2x+12 which is not equal to 2x+8 so your answer is no.