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26.11.2019 •
Mathematics
Apoll showed that 48 out of 120 randomly chosen graduates of california medical schools last year intended to specialize in family practice. what is the width of a 90 percent confidence interval for the proportion that plan to specialize in family practice? select one: a. ± .0736b. ± .0447c. ± .0876d. ± .0894
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Ответ:
± 0.0736
Step-by-step explanation:
Data provided in the question:
randomly chosen graduates of California medical schools last year intended to specialize in family practice, p =
= 0.4
Confidence level = 90%
sample size, n = 120
Now,
For 90% confidence level , z-value = 1.645
Width of the confidence interval = ± Margin of error
= ±
= ±
= ± 0.07356 ≈ ± 0.0736
Hence,
The correct answer is option ± 0.0736
Ответ:
Step-by-step explanation:
it is because of all the dunmb influencers that people have today it is also because of the drugs people take