Mathematics: Aprism and two nets are shown below: image of a right triangular prism and 2 nets. the triangle bases have base 4, height 3, and diagonal side 5. the length of the prism from the bases is 7.2. net a has 3 rectangles in a row. the middle one has sides ac and cd. this middle one has triangle abc on top and identical triangle below. net b is the same except that the triangle base abc is on top of the last rectangle which has sides ac and cd. units are in inches. part a: which is the correct net for

Aprism and two nets are shown below: image of

Ответ:

devinfolds

17.04.2020

Part A: Which is the correct net for the prism?
The correct net for the prism is the Net A, because in the Net B the triangle base ABC, the side AC is incorrect, is not 5 in, the correct is 4 in.

Part B: Write the measurements of Sides AB, BC, and CD of the correct net.
AB=3 in
BC=5 in
CD=7.2 in

Part C: What is the surface area of the prism?

the surface total is=(7.2*5)+(7.2*4)+(7.2*3)+2*(4*3/2)=98.4 in²

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Ответ:

luiscastaenda

14.06.2021

Mathematics

Consider the given quadratic equation that we have :

${:\implies \quad \sf -5x^{2}+5=-2x}$

Multiplying both sides by -1 will yield ;

${:\implies \quad \sf 5x^{2}-5=2x}$

Write the above quadratic equation in the form of standard quadratic equation ax² + bx + c = 0 ,

${:\implies \quad \sf 5x^{2}-2x-5=0}$

Now , comparing this with the standard form of quadratic equation we will get a = 5 , b = -2 , c = -5 . So now , Discriminant (D) = (-2)² - 4 × 5 × -5 = 4 + 100 = 104

Now , by the quadratic formula ;

${:\implies \quad \sf x=\dfrac{-(-2)\pm \sqrt{104}}{2\times 5}}$

${:\implies \quad \sf x=\dfrac{2\pm 2\sqrt{26}}{2\times 5}}$

${:\implies \quad \sf x=\dfrac{\cancel{2}(1\pm \sqrt{26})}{\cancel{2}\times 5}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{x=\dfrac{1\pm \sqrt{26}}{5}}}}$

Used Concepts :-

For any quadratic equation of the form ax² + bx + c , the Discriminant (D) is given by D = b² - 4ac , and the root $\bf x$ of the quadratic equation is given by the quadratic formula as

${\boxed{\bf{x=\dfrac{-b\pm \sqrt{D}}{2a}}}}$

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