erock5528
11.10.2019 •
Mathematics
Aprofessor has learned that nine students in her class of 27 will cheat on the exam. she decides to focus her attention on ten randomly chosen students during the exam.
what is the probability that she finds at least one of the students cheating? (round your intermediate calculations and final answers to 4 decimal places.)
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Ответ:
The probability is 0.9827
Step-by-step explanation:
The probability of the variable X that says the number of students cheating follow a Binomial distribution, because there are:
10 randomly chosen students or n identical and independent eventsA probability of 9/27 that the student is going to cheat or a probability of 1/3 of successSo, the probability P(x) that x students are going to cheat is calculated as:
Then, the probability P that she finds at least one of the students cheating is calculated as:
P = P(x≥1) = P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)
That also can be calculated as:
P = P(x≥1) = 1 - P(x<1) = 1 - P(0)
Therefore, P(0) is calculated as:
P(0) = 0.0173
Finally, P is equal to:
P = 1 - 0.0173 = 0.9827
Ответ:
´The variance is 10000
Step-by-step explanation:
The variance is defined as the square of standard deviation, consequently it is as follows:
σ^2=
σ^2=10000