Mathematics: Aradio active isotope decays according to the exponential decay equations where t is in days.

Aradio active isotope decays according to the exponential

Ответ:

cutebab6723

12.01.2022

Given the equation
$\frac{a}{2} =ae^{-9.876t} \\ \\ \frac{1}{2} =e^{-9.876t} \\ \\ -9.876t=\ln\left( \frac{1}{2} \right)=-0.6931 \\ \\ t= \frac{-0.6931}{-9.876} =0.0702$

Therefore, the half life of the radioactive substance is 0.0702 days = 1.68 hours = 1 hour, 41 minutes, 4 seconds.

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Ответ:

bellam302

03.10.2020

Mathematics

Think about this, starting from x. Then start moving out the of the expression.

Thought process: There is a number x which is multiplied by two, added to five, and then squared.

We can match this with answer choice C.

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Aradio active isotope decays according to the exponential decay equations where t is in days.

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