Mathematics: Aradio station claims that the amount of advertising per hour of broadcast time has an average of 10 minutes and a standard deviation equal to 5 minutes. you listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 8.2 minutes. calculate the z-score for this amount of advertising time. round your answer to 2 decimal places.

Aradio station claims that the amount of advertising

diontna29

10.03.2022

-0.36

Step-by-step explanation:

Given: Mean : $\mu=10\text{ minutes}$

Standard deviation : $\sigma=5\text{ minutes}$

We know that the formula to calculate the z-score is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x=8.2 minutes, we have

$z=\dfrac{8.2-10}{5}=0.36$

Hence, the z-score for this amount of advertising time = -0.36

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