Areas of trapezoids, rhombuses, and kites
find the area of the trapezoid.
hint: use a special triangle.
10 ft
300
8.7ft
12 ft
[? ] ft
enter

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Ответ:

bobiscool3698

12.12.2020

Mathematics

The area of the park is 1,11,739 square feet.

Step-by-step explanation:

Since, the area of a triangle is,

$A=\frac{1}{2}\times s_1\times s_2\times sin\theta$

Where, s_1 and s_2 are the adjacent sides and $\theta$ is the included angle of these sides,

Here, the two adjacent sides of the park are 533 feet and 525 feet, while, the angle included by these sides is 53°.

That is, s_1 = 533 ft, s_2 = 525 ft and $\theta$ = 53°,

Hence, the area of the park is,

$A=\frac{1}{2}\times 533\times 525\times sin 53^{\circ}$

$=\frac{279825\times 0.79863551004}{2}$

$=\frac{223478.181599}{2}=111739.090799\approx 111739\text{ square ft}$

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Areas of trapezoids, rhombuses, and kitesfind the area of the trapezoid.hint: use a special triangle.10 ft3008.7ft12 ft[? ] ftenter