Arectangle has a length of 8 feet and a width of 6 feet if its length and width in creased by 50% each what is the area of the new rectangle

108 ft^2

Step-by-step explanation:

New Length: 8 * 1.5 = 12

New width: 6 * 1.5 = 9

New area = 12 * 9 = 108 ft^2

Hello there!

108 ft²

Step-by-step explanation:

In this question, we are trying to find the new area of a rectangle in which the sides are increased by 50%.

First thing we must do is find the new size of the side lengths (8 and 6).

We will find a 50% increase in 8, and 50% increase in 6.

We would multiply the numbers by 0.5.

8 × 0.5 = 4

6 × 0.5 = 3

Then, we would add those numbers to the side lengths that it belongs to.

8 + 4 = 12

6 + 3 = 9

The increased side lengths would be 12 (length and 9 (width)

To find the area, you would multiply length × height.

12 × 9 = 108

The area of the new rectangle would be 108 ft²