Mathematics: Arectangle has length c and width 2d. another rectangle has length 4 and width (5-c). write a simplified expression of their combined area.

Arectangle has length c and width 2d. another

Ответ:

stephanieeping

12.01.2022

The combined area is area of the first rectangle plus area of the second rectangle.
Area of first rectangle = c x 2d = 2cd
Area of second rectangle = 4(5 - c) = 20 - 4c

Combined area = 2cd + 20 - 4c

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Ответ:

FriesAintHere1392

02.12.2021

Mathematics

Let w and 2w+11 be the width and length of the rectangle, respectively. Then:
w(2w+11)=63
2w²+11w-63=0
(2w-7)(w+9)=0
w=7/2 or -9
Using the positive value, we get dimensions of 7/2 m x 18 m for the rectangle
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Arectangle has length c and width 2d. another rectangle has length 4 and width (5-c). write a simplified expression of their combined area.

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