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10.07.2019 •
Mathematics
Arectangular garden is 5 feet longer than twice its width. it has a sidewalk 3 feet wide on two of its sides. the area of the sidewalk is 213 square feet. find the dimensions of the garden.
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Ответ:
The length and width of the garden are 47 ft and 21 ft respectively.
Explanation
Suppose, the width of the garden is
feet.
As the garden is 5 feet longer than twice its width, so the length will be:![(2x+5) feet](/tpl/images/0073/3443/52f90.png)
So, the area of the garden![= length*width=x(2x+5)ft^2](/tpl/images/0073/3443/b07e4.png)
Now, the garden has a sidewalk 3 feet wide on two of its sides. That means, the length of the garden including the sidewalk
and the width including the sidewalk ![=(x+3)ft](/tpl/images/0073/3443/1b44b.png)
Given that, the area of the sidewalk is 213 ft². So the equation will be.....
So, the width of the garden is 21 feet and the length is![(2*21+5)ft= 47 ft](/tpl/images/0073/3443/686fd.png)
Ответ: